CI is SI on a growing base. For 2 years the only extra over SI is interest on the first year's interest.
With compound interest, last year's interest starts earning interest too. Rs 1,000 at 10% becomes 1,100, then 1,210, then 1,331.
Compound interest questions test the multiplier (1 + R/100)n, the difference between CI and SI, and half-yearly or quarterly compounding.
Amount after n years: A = P (1 + R/100)n. CI = A - P.
Year by year it is successive percentage increases: each year multiplies by (1 + R/100).
Find the compound interest on Rs 10,000 at 10% a year for 3 years.
Answer: 3310
Rs 8,000 at 10% a year compounded half-yearly for 1 year. Amount?
Answer: 8820
For 2 years: CI - SI = P (R/100)2. That is the 'interest on the first year's interest'.
For 3 years: CI - SI = P (R/100)2 (3 + R/100).
The difference between CI and SI on a sum at 10% for 2 years is Rs 50. Find the sum.
Answer: 5000
At compound interest, if a sum doubles in n years it becomes 4 times in 2n, 8 times in 3n. Powers, not multiples.
Rough rule: money doubles in about 72/R years. At 8%, about 9 years.
A sum doubles in 5 years at compound interest. In how many years will it be 8 times?
Answer: 15
Use it when: Build the year-by-year amounts; it is faster than powers.
CI on 10,000 at 10% for 3 years
Answer: Rs 3,310
Difference between CI and SI on Rs 10,000 for 3 years at 10%?
Answer: Rs 310
CI on Rs 16,000 at 20% p.a. compounded quarterly for 9 months?
Answer: Rs 2,522
A sum at CI becomes Rs 6,050 in 2 years and Rs 6,655 in 3 years. Principal?
Answer: Rs 5,000
CI - SI on a sum for 2 years at 5% is Rs 25. The sum?
Answer: Rs 10,000
11 questions with full solutions.